Friday, September 24, 2010

Simple Algebra Problems

Simple algebra problems

Subtract – 4 from – 10.

Solution :
=– 10 – (– 4)

= – 10 + (additive inverse of – 4)

= – 10 + 4

= – 6 (see addition of two integers)

2)Find the product of (a) (+ 6) × (– 5) (b) (– 12) × (+ 12) (c) (– 15) × (– 4)

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Square root

Other helpful links

Formula for diameter of a circle

Friday, September 17, 2010

Growth Equation

Exponential growth equation

A ) y = C(1 - r)t
B ) y = C(1 + r)t
C ) Both
D ) Cannot be determined

Steps to derive

1 y = C(1 - r)t is a model for exponential decay and y = C(1 + r)t is a model for exponential growth.

2 So, the equation y = C(1 - r)t is not an exponential growth model

To know more:

Cubic feet

How to measure cubic feet

Thursday, September 16, 2010

Equilateral Triangle

Triangle equilateral:
Find area and perimeter of a square whose side is 7.5 cm.

Solution:

Side of the square, a = 7.5 cm

Area of the square, A = a2

= a × a

= 7.5 × 7.5

= 56.25cm2

Perimeter of the square, P = 4a

= 4 × 7.5 cm

= 30 cm


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Line plot

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Prime number chart

Wednesday, September 15, 2010

Solving Functions

Solving functions:

The domain set is the set of students and the co-domain set is the set of benches. Each student will occupy only one bench. Each student has seat also. By principle of function, '‘each student occupies a single bench’. Therefore the relation ‘sitting’ is a function from set of Students to set of Benches.

If we interchange the sets, the set of benches becomes the domain set and the set of students becomes co-domain set. Here at least one bench consists of more than one student.

This is against the principle of function i.e. each element in the domain should have associated with only one element in the co-domain. Thus if we interchange the sets, it is not possible to define a function.

To know more:

Prime numbers

Substitution integration

Tuesday, September 14, 2010

Ratio Examples

Ratio Examples:

The allowance of two numbers U and V (V [!=] 0) is the area of the numbers. The numbers U and V are accepted as the agreement of the ratio. Types of arrangement application capricious with example: 1. Compounded ratio-using capricious with example 2. Duplicate ratio-using capricious with example 3. Triplicate ratio-using capricious with example

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11th grade maths

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Mean and standard ratio

Wednesday, September 8, 2010

Circle


Area circle:

Circle is a 2 dimensional figure. In circle there is a diameter and radius. Diameter of a circle is same as the length between two distinct points in a circle which should pass through the center of a circle. The equation of a circle has pi and radius or pi and diameter. Let us see some example problems for the clear understanding of the concepts.

Equation – Area Circle Equation:

The equation to find the area of a circle is times radius2.

The equation to find the area of a circle using diameter is times


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Solve math equation

Deviation

Deviation

Deviation

In order to find percent deviation initially you require to find the Average deviation and Mean. After finding the two things you divide the average deviation in to the mean then multiply by 100% . To Find the average deviation you require to subtract the mean from a measured value. Mean value can be measured as sum the information values and then divide that number by the number of information values.

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Math problems

Bar graphs